Distance between Yekaterinburg, Sverdlovsk Oblast, Russia and Port-de-Paix, Haiti
10453 km = 6495 miles
We assume a spherical Earth as a close approximation of the true shape of the Earth (an oblate spheroid). The distance is calculated as great-circle or orthodromic distance between city centres on the surface of a sphere.
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Yekaterinburg, Russia
Country: RussiaYekaterinburg’s coordinates: 56°51′06″ N, 60°36′43″ E
Population: 1,349,772
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Port-de-Paix, Haiti
Country: HaitiPort-de-Paix’s coordinates: 19°56′20″ N, 72°49′57″ W
Population: 250,000
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